Question

A chemical engineer is studying the two reactions shown in the table below. In each case, he fils a reaction vessel with some mixture of the reactants and products at a constant temperature of 16.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. AH = 951. ) AS = 3289. AG = OW x 5 ? ALGO, 6) + 3H, () - 2A1() + 3H,06) Which is spontaneous? this reaction the reverse reaction neither AH -12. W as=0 AG -26. Sn(s) + 200,6) - S0,6) + 2006) Who spontaneous? the reverse reaction neither

Answer 1

# Al2O3 (s) + 3H2(9) OH = 951 ki T: 16°C -) ► 2Al(s) + 3H20 (9) os= 328 9 J/k => 3-289 kJ/ 16+ 273:15 -7 289.15) on = OH - TOS - 951 - 289.15 X 3-289 on = o k3/mol are. Rh is at eam. so neither rxn is spontaneous # Sn(s) + 2C02 (9) -> SnO2C37 + 2001) OH = -12k] os=? on=-26k] = -12000] T=289. isk on = OH-TOS - 26000 = -12000 - 289.15 0s OS: 48 J/K | here sh=-ive so this Reaction is spontaneous Are