The statistical software output for this problem is:
Two sample proportion summary confidence interval:
p1 : proportion of successes for population 1
p2 : proportion of successes for population 2
p1 - p2 : Difference in proportions
99% confidence interval results:
Difference | Count1 | Total1 | Count2 | Total2 | Sample Diff. | Std. Err. | L. Limit | U. Limit |
---|---|---|---|---|---|---|---|---|
p1 - p2 | 18 | 32 | 8 | 32 | 0.3125 | 0.11640363 | 0.012664123 | 0.61233588 |
Hence,
99% confidence interval for differences in proportion will be:
From 0.0127 to 0.6123
Posted this question yesterday but the answers were wrong. Chapter 10 Homework Question 5 (of 5)...
Chapter 10 Homework Question 5 (of 5) value 10.00 points A study showed hat 18 of 32 coll phone users with a headset missed their ext, compared with 8 of 32 talking to a passenger Construct a 99 percent confidence interval for the difference in proportions. (Round your answers to 4 decimal places.) The 99 percent confidence interval is tr Hints References eBook& Resources Hint 1 Stat= Exam , Re-docx ^ O Type here to search Stat l' Exam 1...
A study showed that 12 of 24 cell phone users with a headset missed their exit, compared with 3 of 24 talking to a passenger. Construct a 95 percent confidence interval for the difference in proportions. (Round your answers to 4 decimal places.) The 95 percent confidence interval is from to .
photos for each question are all in a row (1 point) In the following questions, use the normal distribution to find a confidence interval for a difference in proportions pu - P2 given the relevant sample results. Give the best point estimate for p. - P2, the margin of error, and the confidence interval. Assume the results come from random samples. Give your answers to 4 decimal places. 300. Use 1. A 80% interval for pı - P2 given that...