Question

10.6 Con of Momentum 1' and then Con of Energy) A 0.015 kg bullet is fired horizontally into a 3.0 kg block of wood that is hanging from a very long string. Upon impact, the bullet sticks into the wood and the block (along with the bullet) rises a height of 0.10 meter above the initial level that the wooden block was hanging from prior to impact. What was the initial speed of the bullet before impact? ---- M ----------M +m

Answer 1

Given mass of bullet (m) = 0.015kg mass of Block (M) = 3kg hight Rise(h)= 0.10 case ② consevetion of momentin after collison Before Colucien Now momentum conservation Pp = Pf = my + m2 V2 = mv,+ mave mvoto= (tm) v = (M+m) u m Mtm How Case I ? :0lmito Mint How Energy consvation KE = PE 1 (MM) x ² = rafm) xn. 1² agh v=J2x9.0 xool u=51.96 R = 1.4 m/se

• Tre = 1.46 m/sec / put this vale into the ag ③ 104 = m X vo (Mim) Vo = 1.4 x (M+m) o m Vo = 1.4x 3.015 0.015 Vo = 200. U misec.