) Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving...

Question

Question

) Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of CaF2 in 850.0 g of water.

Answer 1

Answer #1

moles of $CaF_2$ = 0.400

moles of Ca ions = 0.400

moles of fluoride ions = 0.400 $\times$ 2 = 0.800

moles of water = mass/molecular weight = $\frac {850}{18} = 47.23$ moles

mole fraction of all ions = $\frac {moles\ of\ CaF_2}{Total\ number\ of\ moles }$ = $\frac {0.4 + 0.8}{0.4 + 47.23} = 0.0248$

Answer 2

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