Question

A solution is prepared by dissolving 38.6 g sucrose in 495 g water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL.

Answer 1

Answer. Given data,weight of sucrose(solute) = 38.6 g.

                            weight of water(solvent)=495 g.

we know that mole fraction of solute=number of moles of solute/total number of moles of solution.

         number of moles of sucrose n_s=weight of sucrose/gram molecular weight of sucrose.                                   

                        n_s =38.6/342=0.11

number of moles of water n_w =495/18=27.5

      mole fraction of sucrose = n_s/( n_s+ n_w )

                                         =0.11/(0.11+27.5)

                                         =0.11/27.61=0.0040.dilute solution of sucrose.

Mole fraction of sucrose=0.004.