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Vladimirkezerashvili, Ph.D. Students name ase show all your work. Answers without adequate work will receive no credits Carr
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Answer #1

1a] Net magnetic field at center = (u0 I /4a - u0 I/b) where a and b are the radii of semicircular segments

= pi*10^-7*60/0.20 - pi*10^-7*60/0.30

= 3.14*10^-5 T

b] direction will be determined by the direction of magnetic field of smaller semicircle

= into the page

2a) magnetic field B = u0ienclosed/2pir

= 2e-7*3/2e-3 = 0.0003 T

b) again magnetic field B = u0ienclosed/2pir

= 2e-7*(3 -3)/2e-3

= 0 T

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