Question
Show the derivation steps between (22-13) to (22-16) please include descriptions of properties/laws followed. Thank you.
lect all the perpendiculal t Adding Components. We have another omponents are in the positive direction of the z axis, so we can just add p as scalars. Thus we can already tell the direction of the net el the : directly away from the ring. From Fig. 22-12, we see that the paralled a onents each have magnitudedE cos 6, but θ is another illegal symbol el con. eplace cos o with legal symbols by again using the right triangle in Fig write (22-13) ultiplying Eq. 22-12 by Eq. 22-13 gives us the parallel field com ch charge element: ds. cos θ . (22-14) 4π80 (z2 + R2)32 Integrating. Because we must sum a huge number of these components all, we set up an integral that moves along the ring, from element to ele m a starting point (call it s 0) through the full circumference (s 2TR) quantity s varies as we go through the elements; the other symbols in Eq. 22-14 ain the same, so we move them outside the integral. We find (22-15) is afine answer, but we can also switch to the total cdharge by using A-g/2aR) 4z mlR (charged ring). (22-16) charge on the ring is negative, instead of positive as we have assumed,the itude of the field at P is still given by Eq. 22-16. However, the electric r then points toward the ring instead of away from it. et us check Eq. 22-16 for a point on the central axis that is so far away For such a point, the expression z2+ R2 in Eq. 22-16 can be appr and Fa 3.16 bag approximate
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Answer #1

This question is based on the following concepts/laws/properties

1. Properties of cosine

2. Pythagoras Theorem

3. Electric field due to a charge

4. Charge density concept

5. Concept of integration

6. Mathematical simplification.

The detailed solution is described below

Here. We are dedm elechic el AAS on the right ngles tiane, ung Igmajoras meden, we have:- No, Electic eld dE d to fointor Shif Chore

em be ma = 1 Ads abave es

21t 2X (22.15 Als, chage dansig.A is Thu, 22.IS bea- 312

THANKS!!!

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