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Given the system of forces below, calculate
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: Given the system of forces below, calculate Given the system of forces below, calculate: F3...
Given the system of forces below, calculate: F1x = -7 lb. F1y = 7 lb. F1z...
Given the system of forces below, calculate:
F1x = -7 lb. F1y = 7 lb.
F1z = 2 lb. F2x = 7 lb.
F2y = 5 lb. F2z = -7 lb.
F3 = 44 lb. θ = 58 deg
1) Write the F3 force in vector
form.(i,j,k)
2) The resultant force vector of the system. (i,j,k)
3) The magnitude of the resultant force. (lb)
4) The directional cosine alpha
5) The directional cosine beta.
6) The directional cosine gamma.
7)...
For the three force system shown, calculate: For the three force system shown, calculate: 1 F2...
For the three force system shown, calculate:
For the three force system shown, calculate: 1 F2 30 45° 3 COLLAPSE IMAGES F, 281 lb F 85 lb The magnitude of F2 such that the sum of F, F2, and Fs in the x direction is zero. 217.150 1 tries remaining 50 pointfs) possible b ENTER The direction of the resultant force FR deg ENTER 2 tries remaining. 50 pointis) possible
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft...
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
A (O.O.ZA) D (-5, 10, 0) B (15.-10,0) C (20, 25.0) COLLAPSE IMAGES F = 104N...
A (O.O.ZA) D (-5, 10, 0) B (15.-10,0) C (20, 25.0) COLLAPSE IMAGES F = 104N Fo=220N F;= 213N Zx = 41 m Best Score: 1.00/4 Current Score: 0.0074 Find the magnitude of the resultant force acting on the pole at height ZA N ENTER 3 tries remaining 1 points possible Calculate the directional cosine cos(0) ENTER 3ries remaining poids) sossible Calculate the directional cosine cos(5) ENTER 3 tres remaining 1 points) Bossible Calculate the directional cosine cos(V) ENTER 3...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F....
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
The three forces F1, F2 and F3 act on a hook at the angles α1, α2...
The three forces F1, F2 and F3 act on a hook at the angles
α1, α2 and α3 as shown in the figure.
1.) Find the x component of the resultant force in pounds:
2.) Find the y component of the resultant force in
pounds(Fr):
The three forces F1, F2 and Fs act on a hook at the angles a1, a2 and a3 as shown in the figure. F2 F3 a3 COLLAPSE IMAGES F1-103 lb F2-227 lb F3-286 lb ai-38...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and calculate: Note: On your FBD draw all internal forces in the positive direction (tension). F1 lb F, Ib F, lb 6 0° F2 lb 4 ft 6ft B 6ft G 6ft 1 h ft h ft Fs lb COLLAPSE IMAGES F1 80 lb F2 240 lb F3 405 lb 0 80 deg h 10 ft Best Score: 2.00/5 Current Score: 2.00/5 The force in...
The given steel vertical pole supports 3 traffic lights and a visibility light. The visibility light...
The given steel vertical pole supports 3 traffic lights and a visibility light. The visibility light is directly above the nearest traffic light. The weight of each traffic light is Wild and the weight of the visibility light is W. 15. The unit weight of steel is y lb/ft'. The cross-section of each support pole is hollow and is shown below. Replace the traffic light structure and lighting with an equivalent system at O. Calculate: W lb 10ft AB W...
The truss is supported by wheels at A and a hinge at B and subjected to...
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
In the figure shown below, there is a rectangular load distribution acting on the beam. Calculate:...
In the figure shown below, there is a rectangular load distribution acting on the beam. Calculate: Note: Draw all reactions in the positive x and y directions. w lb/ft L/2 ft L ft COLLAPSE IMAGES O hours : 51 minutes : 37 seconds * = 80 lb/ft L-aft The magnitude of the resultant force from the rectangular distributed load. 16 ENTER 8 t rening point possible The location of the resultant force of the rectangular distributed load measured from A....
Given the system of forces below, calculate:
F1x = -7 lb. F1y = 7 lb.
F1z = 2 lb. F2x = 7 lb.
F2y = 5 lb. F2z = -7 lb.
F3 = 44 lb. θ = 58 deg
1) Write the F3 force in vector
form.(i,j,k)
2) The resultant force vector of the system. (i,j,k)
3) The magnitude of the resultant force. (lb)
4) The directional cosine alpha
5) The directional cosine beta.
6) The directional cosine gamma.
7)...
For the three force system shown, calculate:
For the three force system shown, calculate: 1 F2 30 45° 3 COLLAPSE IMAGES F, 281 lb F 85 lb The magnitude of F2 such that the sum of F, F2, and Fs in the x direction is zero. 217.150 1 tries remaining 50 pointfs) possible b ENTER The direction of the resultant force FR deg ENTER 2 tries remaining. 50 pointis) possible
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
A (O.O.ZA) D (-5, 10, 0) B (15.-10,0) C (20, 25.0) COLLAPSE IMAGES F = 104N Fo=220N F;= 213N Zx = 41 m Best Score: 1.00/4 Current Score: 0.0074 Find the magnitude of the resultant force acting on the pole at height ZA N ENTER 3 tries remaining 1 points possible Calculate the directional cosine cos(0) ENTER 3ries remaining poids) sossible Calculate the directional cosine cos(5) ENTER 3 tres remaining 1 points) Bossible Calculate the directional cosine cos(V) ENTER 3...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
The three forces F1, F2 and F3 act on a hook at the angles
α1, α2 and α3 as shown in the figure.
1.) Find the x component of the resultant force in pounds:
2.) Find the y component of the resultant force in
pounds(Fr):
The three forces F1, F2 and Fs act on a hook at the angles a1, a2 and a3 as shown in the figure. F2 F3 a3 COLLAPSE IMAGES F1-103 lb F2-227 lb F3-286 lb ai-38...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and calculate: Note: On your FBD draw all internal forces in the positive direction (tension). F1 lb F, Ib F, lb 6 0° F2 lb 4 ft 6ft B 6ft G 6ft 1 h ft h ft Fs lb COLLAPSE IMAGES F1 80 lb F2 240 lb F3 405 lb 0 80 deg h 10 ft Best Score: 2.00/5 Current Score: 2.00/5 The force in...
The given steel vertical pole supports 3 traffic lights and a visibility light. The visibility light is directly above the nearest traffic light. The weight of each traffic light is Wild and the weight of the visibility light is W. 15. The unit weight of steel is y lb/ft'. The cross-section of each support pole is hollow and is shown below. Replace the traffic light structure and lighting with an equivalent system at O. Calculate: W lb 10ft AB W...
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
In the figure shown below, there is a rectangular load distribution acting on the beam. Calculate: Note: Draw all reactions in the positive x and y directions. w lb/ft L/2 ft L ft COLLAPSE IMAGES O hours : 51 minutes : 37 seconds * = 80 lb/ft L-aft The magnitude of the resultant force from the rectangular distributed load. 16 ENTER 8 t rening point possible The location of the resultant force of the rectangular distributed load measured from A....
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