Question

Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and calculate: Note: On your FBD draw al
F1 80 lb F2 240 lb F3 405 lb 0 80 deg h 10 ft Best Score: 2.00/5 Current Score: 2.00/5 The force in member IG. 1/1 pts System
The force in member IH 1/1 pts System Answer: 300 The force in member HF lb ENTER 3 tries remaining. 1 point(s) possible The
0 0
Add a comment Improve this question Transcribed image text
Answer #1


Sol S01 21 FH 300 Ib (T) 8 HI Εμ : 351.31 812 lb(7)

Add a comment
Know the answer?
Add Answer to:
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The length of each member in the truss is L feet. Note: On your FBD draw...

    The length of each member in the truss is L feet. Note: On your FBD draw all internal forces in the positive direction (tension). F3 lb с / Fulb F4 lb V 1600 600 Filb E F. lb F1 = 17 lb F2 = 26 lb F3 = 31 lb F4 = 29 lb F5 = 19 16 F6 = 53 lb L = 8 ft The force in member ED. ENTER 3 tries remaining. 1 point(s) possible The force...

  • やrcurPoint や rourPoint For The Given Truss, C/X G For the sy metrical t /X e...

    やrcurPoint や rourPoint For The Given Truss, C/X G For the sy metrical t /X e The Length or Each M × e The Weight or The Tru e Civil Engineering que -) С https://www.msufourpoint.com/flassessment/1718/214/Homework%2010 FourPoint Course - 4 LogoutMICHIGAN STATE UNIVERSITY Q.1 For the symmetrical truss, use the method of joints and calculate Note: On your FBD draw all internal forces in the positive direction (tension) Q.2 Q.3 F1 lb F, lb Q.4 Q.5 F2 lb 6 ft B...

  • Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI...

    Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...

  • Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section...

    Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...

  • For the truss, use the method of sections Note: On your FBD draw all internal forces...

    For the truss, use the method of sections Note: On your FBD draw all internal forces in the positive direction (tension. FkN FKN PKN A 0.51 m F Im FKNM COLLAPSE IMAGES F = 53 KN P = 98 N h 3m 1 = 5m 0.35 deg Best Score: 4.00 / 5 F = 53 kN P = 98 kN h = 3m /=5 m = 35 deg Best Score: 4.00/5 Current Score: 0.00 / 5 Calculate A. (the x...

  • The x component of the support reaction at A, Ax: 10 / 10 pts System Answer:...

    The x component of the support reaction at A, Ax: 10 / 10 pts System Answer: 0 The y component of the support reaction at 10/10 pts System Answer: 214.8 The y component of the support reaction at B, By. 10 / 10 pts System Answer: 219.2 The shear force equation for section 1. 1 6 ENTER ENTER * 2 tries remaining. 15 point(s) possible The bending moment equation for section 1. ENTER 3 tries remaining. 20 point(s) possible Q1...

  • The truss is supported by wheels at A and a hinge at B and subjected to...

    The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...

  • The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft...

    The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT