Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and...
The length of each member in the truss is L feet. Note: On your FBD draw all internal forces in the positive direction (tension). F3 lb с / Fulb F4 lb V 1600 600 Filb E F. lb F1 = 17 lb F2 = 26 lb F3 = 31 lb F4 = 29 lb F5 = 19 16 F6 = 53 lb L = 8 ft The force in member ED. ENTER 3 tries remaining. 1 point(s) possible The force...
やrcurPoint や rourPoint For The Given Truss, C/X G For the sy metrical t /X e The Length or Each M × e The Weight or The Tru e Civil Engineering que -) С https://www.msufourpoint.com/flassessment/1718/214/Homework%2010 FourPoint Course - 4 LogoutMICHIGAN STATE UNIVERSITY Q.1 For the symmetrical truss, use the method of joints and calculate Note: On your FBD draw all internal forces in the positive direction (tension) Q.2 Q.3 F1 lb F, lb Q.4 Q.5 F2 lb 6 ft B...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
For the truss, use the method of sections Note: On your FBD draw all internal forces in the positive direction (tension. FkN FKN PKN A 0.51 m F Im FKNM COLLAPSE IMAGES F = 53 KN P = 98 N h 3m 1 = 5m 0.35 deg Best Score: 4.00 / 5 F = 53 kN P = 98 kN h = 3m /=5 m = 35 deg Best Score: 4.00/5 Current Score: 0.00 / 5 Calculate A. (the x...
The x component of the support reaction at A, Ax: 10 / 10 pts System Answer: 0 The y component of the support reaction at 10/10 pts System Answer: 214.8 The y component of the support reaction at B, By. 10 / 10 pts System Answer: 219.2 The shear force equation for section 1. 1 6 ENTER ENTER * 2 tries remaining. 15 point(s) possible The bending moment equation for section 1. ENTER 3 tries remaining. 20 point(s) possible Q1...
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...