Homework Answers
Add Answer to:
For the truss, use the method of sections Note: On your FBD draw all internal forces...
The length of each member in the truss is L feet. Note: On your FBD draw...
The length of each member in the truss is L feet. Note: On your FBD draw all internal forces in the positive direction (tension). F3 lb с / Fulb F4 lb V 1600 600 Filb E F. lb F1 = 17 lb F2 = 26 lb F3 = 31 lb F4 = 29 lb F5 = 19 16 F6 = 53 lb L = 8 ft The force in member ED. ENTER 3 tries remaining. 1 point(s) possible The force...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and calculate: Note: On your FBD draw all internal forces in the positive direction (tension). F1 lb F, Ib F, lb 6 0° F2 lb 4 ft 6ft B 6ft G 6ft 1 h ft h ft Fs lb COLLAPSE IMAGES F1 80 lb F2 240 lb F3 405 lb 0 80 deg h 10 ft Best Score: 2.00/5 Current Score: 2.00/5 The force in...
Consider the diagram below: Note: On your FBD draw all internal forces in the positive direction...
Consider the diagram below: Note: On your FBD draw all internal forces in the positive direction (tension). RN QN E SN PN TNB а т т а т т а т т т а т COLLAPSE IMAGES P = 113N Q = 312 N R = 129 N S = 82 N T = 81 N = 45 deg a = 2 m Determine the force in member EB N ENTER 3 tries remaining. 1 point(s) possible
: Given the system of forces below, calculate Given the system of forces below, calculate: F3...
:
Given the system of forces below, calculate
Given the system of forces below, calculate: F3 COLLAPSE IMAGES Write the F force in vector form k lb ENTER 3 tries remaining. 1 poinf(s) possible The resultant force vector of the system. k lb ENTER 3 tries remaining. 1 paint s) possible The magnitude of the resultant force. b ENTER 3 tries remaining. 1 paint's) possible The directional cosine alpha. ENTER 3 tries remaining. 1 paints) possible The directional cosine beta....
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft...
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
P lb Q lb .5 0.5L F lb COLLAPSE IMAGES Q=192b P#112b F:53 lb h=7ft L=13ft...
P lb Q lb .5 0.5L F lb COLLAPSE IMAGES Q=192b P#112b F:53 lb h=7ft L=13ft α=27 deg β-80 deg The reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at E lb ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at E NIR
If the acting force is P, determine the normal and frictional forces acting on the mi...
If the acting force is P, determine the normal and frictional forces acting on the mi kg and m2 kg crate. The static coefficient of friction is .3. The pulley is frictionless. Calculate the force P to keep the crates in equilibrium. mi m2 m1 = 19 kg m2 = 71 kg $ = 20 deg 0 = 30 deg The normal force of m1. ENTER 3 tries remaining. 1 point(s) possible The maximum frictional force of m1. 2 ENTER...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F....
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
The x component of the support reaction at A, Ax: 10 / 10 pts System Answer:...
The x component of the support reaction at A, Ax: 10 / 10 pts System Answer: 0 The y component of the support reaction at 10/10 pts System Answer: 214.8 The y component of the support reaction at B, By. 10 / 10 pts System Answer: 219.2 The shear force equation for section 1. 1 6 ENTER ENTER * 2 tries remaining. 15 point(s) possible The bending moment equation for section 1. ENTER 3 tries remaining. 20 point(s) possible Q1...
For the beam shown, draw the reactions at supports A and B in the positive direction,...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
The length of each member in the truss is L feet. Note: On your FBD draw all internal forces in the positive direction (tension). F3 lb с / Fulb F4 lb V 1600 600 Filb E F. lb F1 = 17 lb F2 = 26 lb F3 = 31 lb F4 = 29 lb F5 = 19 16 F6 = 53 lb L = 8 ft The force in member ED. ENTER 3 tries remaining. 1 point(s) possible The force...
Logout Course Q2 Weight: 20.00 % For the symmetrical truss, use the method of joints and calculate: Note: On your FBD draw all internal forces in the positive direction (tension). F1 lb F, Ib F, lb 6 0° F2 lb 4 ft 6ft B 6ft G 6ft 1 h ft h ft Fs lb COLLAPSE IMAGES F1 80 lb F2 240 lb F3 405 lb 0 80 deg h 10 ft Best Score: 2.00/5 Current Score: 2.00/5 The force in...
Consider the diagram below: Note: On your FBD draw all internal forces in the positive direction (tension). RN QN E SN PN TNB а т т а т т а т т т а т COLLAPSE IMAGES P = 113N Q = 312 N R = 129 N S = 82 N T = 81 N = 45 deg a = 2 m Determine the force in member EB N ENTER 3 tries remaining. 1 point(s) possible
:
Given the system of forces below, calculate
Given the system of forces below, calculate: F3 COLLAPSE IMAGES Write the F force in vector form k lb ENTER 3 tries remaining. 1 poinf(s) possible The resultant force vector of the system. k lb ENTER 3 tries remaining. 1 paint s) possible The magnitude of the resultant force. b ENTER 3 tries remaining. 1 paint's) possible The directional cosine alpha. ENTER 3 tries remaining. 1 paints) possible The directional cosine beta....
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
P lb Q lb .5 0.5L F lb COLLAPSE IMAGES Q=192b P#112b F:53 lb h=7ft L=13ft α=27 deg β-80 deg The reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at E lb ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at E NIR
If the acting force is P, determine the normal and frictional forces acting on the mi kg and m2 kg crate. The static coefficient of friction is .3. The pulley is frictionless. Calculate the force P to keep the crates in equilibrium. mi m2 m1 = 19 kg m2 = 71 kg $ = 20 deg 0 = 30 deg The normal force of m1. ENTER 3 tries remaining. 1 point(s) possible The maximum frictional force of m1. 2 ENTER...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
The x component of the support reaction at A, Ax: 10 / 10 pts System Answer: 0 The y component of the support reaction at 10/10 pts System Answer: 214.8 The y component of the support reaction at B, By. 10 / 10 pts System Answer: 219.2 The shear force equation for section 1. 1 6 ENTER ENTER * 2 tries remaining. 15 point(s) possible The bending moment equation for section 1. ENTER 3 tries remaining. 20 point(s) possible Q1...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
Most questions answered within 3 hours.
-
Work of 1950 J is done by stirring a perfectly insulated beaker
containing 75 g of...
asked 25 minutes ago -
The neighborhood kids set up an outdoor lemonade stand in
Maryland in June. They find that...
asked 27 minutes ago -
9. A company has a beginning inventory of 4,000 units. The
company estimates it will sell...
asked 40 minutes ago -
A patient goes to the doctor's office with symptoms of a urinary
tract infection and provides...
asked 42 minutes ago -
When responding to the essay questions, be sure to cite any
material you obtained from a...
asked 42 minutes ago -
The energy of an electron in a 2.25-eV-deep potential well is
1.50 eV.At what distance into...
asked 44 minutes ago -
Q1:Which three evolutionary innovations are present in land
plants (but not all land plants) that allowed...
asked 47 minutes ago -
Lymphosarcoma is
extremely rare. Risk factors for the disease are largely unknown.
What kind of study...
asked 49 minutes ago -
The solubility of benzoic acid in water is:
0.29g/100mL at 20°C
6.8g/100mL at 100°C
a) What...
asked 51 minutes ago -
Which food law was passed in 1996 and changed how pesticide
residues on food were regulated...
asked 1 hour ago -
companies either hire outside programmers to
write_____ software or use their own internal developers.
asked 1 hour ago -
A magnetic dipole m(t) = m_0*cos(ωt) can be
described as current density j(r,t) = −cm(t) ×...
asked 1 hour ago