Question

The length of each member in the truss is L feet. Note: On your FBD draw all internal forces in the positive direction (tensiF1 = 17 lb F2 = 26 lb F3 = 31 lb F4 = 29 lb F5 = 19 16 F6 = 53 lb L = 8 ft The force in member ED. ENTER 3 tries remaining. 1The force in member CB. ENTER 3 tries remaining. 1 point(s) possible The force in member CD. Ib ENTER 3 tries remaining. 1 po

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Answer #1

1.Given Truss 1 312h си 0 26 sin6oo 1 26 lb , 29 singo cosinsoo 1 l 18600 Go N 2600 1 600 / 160 29 lb 29 casso 26lb4060° ... 60

2.avaz 82.816 lb joint a Considering t. 10 FAG loseb cos 602 / sin 60 = 3/2 alb FAB ___ZF-20 - FAG& FAB co 60° + 105 lb zo. 1 8

3.Joint & /2186 600 60 Sfx 20 Fie cosso. fio cosso e fige Fco {fyzo fcg sin 60° + Frosinbo +31 20 2Fco sin 60 2-31 - FCB 2 -3

4.

Joint B Efx20 26 sinboo FBC FBD + FB ( * 1/2 + F BG * 1/2 +26*2² zFAB*£ 26uobo *.2600 S Bp 60 Vil60° N FAB í FBG 2FBD 2 FAB-

Forces in all the members are calculated with all details as shown.

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