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P lb Q lb .5 0.5L F lb COLLAPSE IMAGES Q=192b P#112b F:53 lb h=7ft L=13ft...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F....
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w...
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
Consider the following picture. goA W lb COLLAPSE IMAGES F2 = 31 lb W=93 b =...
Consider the following picture. goA W lb COLLAPSE IMAGES F2 = 31 lb W=93 b = 42 deg Find the magnitude of the force F, to keep the system in equilibrium. ENTER 3 tres remaining points) Sossible Find the direction of the force F, measured counter clockwise from the positive X-axis to keep the system in equilibrium deg ENTER stries remaining points possible
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft...
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
w = 50 lb/ft P = 57 lb L= 7 ft a = 5 ft b...
w = 50 lb/ft P = 57 lb L= 7 ft
a = 5 ft b = 1 ft ? = 63 deg
w lb/ft P lb L ft b ft Ay COLLAPSE IMAGES The horizontal reaction at A. b ENTER The vertical reaction at A b ENTER The vertical reaction at B ENTER Develop the shear and mement equations along the beam. Section 1 Range 3 resremaningon section Currentceam score: t CHECK RANGE
The truss is supported by wheels at A and a hinge at B and subjected to...
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
For the beam shown, draw the reactions at supports A and B in the positive direction,...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes and the floor is 0.3. Michael's weight of M lb is equally distributed to both of his feet. Michael is trying to slide the W lb refrigerator on the kitchen floor. If Michael's hands are inclined at 20° from the horizontal, calculate: W lb 1.5' 1.5' 12 Αμα 0.5M 4.5' E F S N COLLAPSE IMAGES W = 279 lb M = 153 lb...
COLLAPSE IMAGES Fx = 55 lb F-60 lb β=22 deg The magnitude of the force F. lb ENTER 3 tries remaining. 1 point(s) possible The magnitude of the y component of the force F. lb ENTER 3 tries remaining. 1 point(s) possible
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
Consider the following picture. goA W lb COLLAPSE IMAGES F2 = 31 lb W=93 b = 42 deg Find the magnitude of the force F, to keep the system in equilibrium. ENTER 3 tres remaining points) Sossible Find the direction of the force F, measured counter clockwise from the positive X-axis to keep the system in equilibrium deg ENTER stries remaining points possible
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
w = 50 lb/ft P = 57 lb L= 7 ft
a = 5 ft b = 1 ft ? = 63 deg
w lb/ft P lb L ft b ft Ay COLLAPSE IMAGES The horizontal reaction at A. b ENTER The vertical reaction at A b ENTER The vertical reaction at B ENTER Develop the shear and mement equations along the beam. Section 1 Range 3 resremaningon section Currentceam score: t CHECK RANGE
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes and the floor is 0.3. Michael's weight of M lb is equally distributed to both of his feet. Michael is trying to slide the W lb refrigerator on the kitchen floor. If Michael's hands are inclined at 20° from the horizontal, calculate: W lb 1.5' 1.5' 12 Αμα 0.5M 4.5' E F S N COLLAPSE IMAGES W = 279 lb M = 153 lb...
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