The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes...
Talking Auni Michael Alles A refrigerator with weight distribution of W i and W 2 is acted on by a cable whose tension is T 16. The refrigerator is also subjected to a force, P lb. The coefficient of static friction between the refrigerator and the floor is 0.25. Calculate: Tlb 2.5' Plb w O hours : 53 minutes : 21 seconds W1 = 170 lb W2 - 230 lb P - 120 lb T - 180 tba - 30...
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
The plane ABC is hinged along BC. The force F is acting at 90° to the plane. Calculate: NG B(0, 0, Zb) ft F lb →Y C (0, Yc, 0) ft A(Xq, 0, 0) ft R + COLLAPSE IMAGES F = 278 lb Xa = 3 ft Zb= 8 ft Yc = 7 ft The force F in vector form. Oi + @j + OK ENTER 3 tries remaining. 1 point(s) possible The moment around B. Ci + Ok lb.ft...
w lb/ft bft Cross section CC' l ft at B. W. rPoint Course A The horizontal reaction at A. b ENTER 3 tries remaining. 1 pointis) possible The vertical reaction at A lb ENTER 3 tries remaining. 1 points) possible The range for section 1. t ENTER 3 tries remaining. 1 point's) possible The shear force equation for section 1. b ENTER 3 tries remaining. 1 point/s) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining....
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. W lb A Lft Lft COLLAPSE IMAGES W = 248 lb L = 7 Calculate the vertical reaction (Ay) at support A ID ENTER 3 tries remaining. 1 point(3) possible Calculate the horizontal reaction (Ax) at support A ID ENTER 3 tries remaining, 1 point(s) possible Calculate the vertical...