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Talking Auni Michael Alles A refrigerator with weight distribution of W i and W 2 is...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes and the floor is 0.3. Michael's weight of M lb is equally distributed to both of his feet. Michael is trying to slide the W lb refrigerator on the kitchen floor. If Michael's hands are inclined at 20° from the horizontal, calculate: W lb 1.5' 1.5' 12 Αμα 0.5M 4.5' E F S N COLLAPSE IMAGES W = 279 lb M = 153 lb...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
The plane ABC is hinged along BC. The force F is acting at 90° to the...
The plane ABC is hinged along BC. The force F is acting at 90° to the plane. Calculate: NG B(0, 0, Zb) ft F lb →Y C (0, Yc, 0) ft A(Xq, 0, 0) ft R + COLLAPSE IMAGES F = 278 lb Xa = 3 ft Zb= 8 ft Yc = 7 ft The force F in vector form. Oi + @j + OK ENTER 3 tries remaining. 1 point(s) possible The moment around B. Ci + Ok lb.ft...
For the beam shown, draw the reactions at supports A and B in the positive direction,...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
w lb/ft bft Cross section CC' l ft at B. W. rPoint Course A The horizontal...
w lb/ft bft Cross section CC' l ft at B. W. rPoint Course A The horizontal reaction at A. b ENTER 3 tries remaining. 1 pointis) possible The vertical reaction at A lb ENTER 3 tries remaining. 1 points) possible The range for section 1. t ENTER 3 tries remaining. 1 point's) possible The shear force equation for section 1. b ENTER 3 tries remaining. 1 point/s) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining....
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w...
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
w lb/ft Wlb M Ib-ft hft b ft Cross section EE l, ft ft 2 W....
w lb/ft Wlb M Ib-ft hft b ft Cross section EE l, ft ft 2 W. a m FourPoint Course The vertical reaction at B. b ENTER 3 tries remaining. 1 point's) possibie The range for section 1. ft ENTER 3 tries remaining. 1 pointis) possible The shear force equation for section 1 b ENTER 3 tries remaining. 1 pointis) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining. 1 poinns) possible The range for section...
For the beam shown, draw the reactions at supports A and B in the positive direction,...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction,...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
The ps between the refrigerator and the floor is 0.4 and the ps between Michael's shoes and the floor is 0.3. Michael's weight of M lb is equally distributed to both of his feet. Michael is trying to slide the W lb refrigerator on the kitchen floor. If Michael's hands are inclined at 20° from the horizontal, calculate: W lb 1.5' 1.5' 12 Αμα 0.5M 4.5' E F S N COLLAPSE IMAGES W = 279 lb M = 153 lb...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...
Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...
The plane ABC is hinged along BC. The force F is acting at 90° to the plane. Calculate: NG B(0, 0, Zb) ft F lb →Y C (0, Yc, 0) ft A(Xq, 0, 0) ft R + COLLAPSE IMAGES F = 278 lb Xa = 3 ft Zb= 8 ft Yc = 7 ft The force F in vector form. Oi + @j + OK ENTER 3 tries remaining. 1 point(s) possible The moment around B. Ci + Ok lb.ft...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
w lb/ft bft Cross section CC' l ft at B. W. rPoint Course A The horizontal reaction at A. b ENTER 3 tries remaining. 1 pointis) possible The vertical reaction at A lb ENTER 3 tries remaining. 1 points) possible The range for section 1. t ENTER 3 tries remaining. 1 point's) possible The shear force equation for section 1. b ENTER 3 tries remaining. 1 point/s) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining....
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
w lb/ft Wlb M Ib-ft hft b ft Cross section EE l, ft ft 2 W. a m FourPoint Course The vertical reaction at B. b ENTER 3 tries remaining. 1 point's) possibie The range for section 1. ft ENTER 3 tries remaining. 1 pointis) possible The shear force equation for section 1 b ENTER 3 tries remaining. 1 pointis) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining. 1 poinns) possible The range for section...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
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