18. Find the area under the normal curve between z--1.25 and z-1.0 a) .7486 19. If...
12. Using the letters arrangements of the letters is: a) 30 in "BANANA", since there are 3 As, and 2 Ns, the number of different or distinct 13. You decide to watch 4 shows. If there are 8 shows from which to choose, then in how many ways can you select the 4 shows you will watch? a) 32 14. Find the mean of a binomial distibution where n 4 and 15. Find the standard deviation of a binomial distribution...
12. Using the letters in "BANANA", since there are 3 As, and 2 Ns, the number of different arrangements of the letters is: a) 30 c) 120 d)720 e) none of these 13. You decide to watch 4 shows. If there are 8 shows from which to choose, then in how you select the 4 shows you will watch? 70 c) 256 d) 1680 ) none of these c) 1.5 c) 1.5 14. Find the mean of a binomial distribution...
Please ignore the circled choices. I am double checking my work. Find the area ynder the normal curve to the right of 2-67 a) 7486 4214 813 1056 e) .7357 α) .7486 b) .2514 с).8413 0.1056 (9.7357 proportion of soores less than 18. Find the area under the noemal curve between -1.25 and-1. 19. Ir 10 scores are nomally distibuted with a mean o 20. Same as above except find the proportion of sooees greater 21. Consider a university with...
Please ignore the circled answers. I am checking my results. a)2.45 b).2 02 4) 2.95 ) 025 23- /What is the effect of choosing a larger sample size for the sampling distribution? mean increases, standard deviation unchanged b) mean decreases, standaed deviation unchanged c) mean unchanged, standard deviation increases d) mean unchanged, standaed deviation decrases e) no effect As sample size increases little dispersion resulting in sample means falling relatively a) increases, far from b) decreases far from e) increases,...
please answer 22, thanks 21. Consider a university with a population mean GPA of 2.95, a standard deviation of .2, and a sampling distribution of all possible samples of size 100. The mean of the sample means is equal to: a) 245b) 2 .02 2.95 e) .025 Same as above, the standard deviation of the sample means is equal to: a)2.45 22. b) .2 d) 2.95 e) .025
What proportion of a normal distribution is located between each of the following Z-score boundaries? a. z= -0.50 and z= +0.50 b. z=-0.90 and z= +0.90 c. z=-1.50 and z= 1.50 For a normal distribution with a mean of μ = 80 and a standard deviation of σ= 20, find the proportion of the population corresponding to each of the following. a. Scores greater than 85. b. Scores less than 100. c. Scores between 70 and 90. IQ test scores are standardized to produce a normal distribution with...
Determine the area under the standard normal curve that lies between the following values. z=0.6 and z = 1.4 0 0.7257 0.2743 0.9192 0.1935 Assume that the random variable X is normally distributed, with mean p = 90 and standard deviation c = 12. Compute the probability P(X < 105). 0.9015 0.8944 0.8849 ОО 0.1056 The sampling distribution of the sample mean is shown. If the sample size is n = 25, what is the standard deviation of the population...
Respond True or False to each of these statements. The total area under the normal distribution is equal to 1. As the sample size increases, the distribution of the sample statistics becomes more consistent. Sampling variability refer to a variability of parameters. A sampling distribution describes a distribution of sample statistics. All variables that are approximately normally distributed can be transformed to standard z-scores. The z-value corresponding to a datum below the mean is always negative. The area under the...
#3 One of the most common ways of measuring intelligence is the IQ test. IQ scores in the US population have an average of µ = 100 and a standard deviation of σ = 15. Suppose a researcher wanted to test whether socioeconomic status (SES) has an effect on IQ scores. The researcher takes a random sample of n = 100 people, selected from a list of the 1000 richest people in the United States. a. Based on this information,...
For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 97, 94, 95. Use a sample size of 3. The mean of the population is Round to two...