here,
B)
for t1 = 5 s
the distance travelled , s1 = (20 - 0) * ( 5 - 0)
s1 = 100 m
C)
for t2 = 9 s
the distance travelled , s2 = (20 - 0) * ( 9 - 0) + 0.5 * ( 45 - 20) * ( 9 - 5)
s2 = 230 m
D)
for t3 = 13 s
the distance travelled , s3 = (20 - 0) * ( 11 - 0) + 0.5 * ( 45 - 20) * ( 9 - 5) + 0.5 * ( 45 - 20) * ( 11 - 9) + 0.5 * 20 * (13 - 11 )
s3 = 315 m
I’m lost on these ones Constants Correct The graph in (Figure 1) shows the veloaity of...
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Please show work, THANK YOU! 2.31The graph in Fig. E2.31 shows the velocity of a motor- cycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at t-3 s, t - 7 s, and t-11 s. (b) How far does the officer go in the first 5 s? The first 9 s? The first 13 s? Figure E2.31 Vx (m/s) 50 45 40 35 30 25 20 15 t (s) 02 4 6 8 10 12...
ation fects 2.31 The graph in Fig. E2.31 shows the velocity of a motor- cycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at t=3 s, t=7 s, and t= 11 s. not car(b) How far does the officer go in the first 5 s? The first 9 s? The s of first 13 s? ur- to Figure E2.31 LH ave ct. To pe er at Ux (m/s) 50 45 40 35 30 25 20...
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