A 6.89 kg box sled is coasting across frictionless ice at a speed of 2.87 m/s...
Homework Answers
Given that
m1 = 6.89 kg
v1 = 2.87 m/s
m2 = 22.3 + 6.89 = 29.19 kg
v2 = ?
From conservation of momentum we have
Pi = Pf
m1v1 = m2v2
==> v2 = m1v1 / m2
= 6.89 * 2.87 / 29.19
= 0.6774 m/s
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