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My NoteB 13- points SerPSE9 12P025. A uniform plank of length 2.00 m and mass 28.5 kg is supported by three ropes as indicated by the blue vectors in the figure below. Find the tension in each rope when a 715 N person is d 0,425 m from the left end ITI I IT2I 40.0° 2,0K) in Need Help? Read

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Answer #1

ΣMleft end=0

715*0.425 + 28.5*9.81*1 = 2*T1sin(40)

583.46 = 2*T1*0.643

T1 = 583.46/1.286

T1= 453.70 N

ΣFx=0

T3=T1cos40

= 453.70*cos40

= 453.70*0.766

= 347.53 N

ΣFy=0

-715 - 28.5*9.81 + T2 + T1sin40 = 0

T2 = (715 +28.5*9.81)- (453.7*0.643) = 702.85 N

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