Question

Student	Test Score	Student	Test Score	Student	Test Score
1	30	13	26	25	9
2	29	14	43	26	36
3	33	15	43	27	61
4	62	16	68	28	79
5	59	17	63	29	57
6	63	18	42	30	46
7	80	19	51	31	70
8	32	20	45	32	31
9	60	21	22	33	68
10	76	22	30	34	62
11	13	23	40	35	56
12	41	24	26	36	36

A) Report the sample mean and sample standard deviation

B) Construct a 95% confidence interval for the population mean

C) Conduct a t-test to test the hypothesis that the population mean is 60 against the alternative that is not equal to 60.

Ho: u=60

H1: u =/ 60

Answer 1

a)

mean	46.88889
sd	18.5992

b)

95% confidence interval

(mean - t * sd/sqrt(n) , mean + t * sd/sqrt(n))

here n = 36

df =n-1 = 35

t = 2.030108

( 46.8889 - 2.03018 * 18.5992/sqrt(36) , 46.8889 + 2.03018 * 18.5992/sqrt(36) )

=( 40.5956 , 53.1822)

c)

since 60 is not present in confidence interval

we reject the null hypothesis

we conclude that there is evidence that mean is not equal to 60