Let A be the event that a student takes math, B be the event that a student takes science. Then we are given that
P(A) = 62% =0.62 , P(B) = 49% =0.49 and P(A B ) = 0.38
. We have to calculate the percentage of students that take at
least one science or math course. In probability theory, at least
one is given by A
B. Hence we have
to calculate P(A
B). Using
probability formula of set theory P(A
B) is given
by
P(AB) = P(A) + P(B)
- P(A
B ) = 0.62+0.49
-0.38 = 0.73
Hence 73% students take at least one science or math course.
#3. In the freshmen class, 62% of the students take Math, 49% take Science, and 38%...
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