Question

HANDL SSCREW JAw LINK cta sh det ANDLE d C 15 ° 32 35 1.2 in 3.01 in 2.07 in 1.01 in Find the forces indicated in the table below when the locking pliers are gripped with F-46 lbs of force. - Denote rightward or upward forces with positive values; leftward or downward forces with negative values - Resultant magnitudes are all positive. The magnitude and a exerts a on this this At this of the resultant horizontal vertical body. body force is: point, force of force of: ew -37.681 lb upper hendle A lower hendle Jaw ink lower handle C upper handie 37.681 lb 26.3845 lb link D bolt upper handle bolt jaw boit bolt Note: With this magnitude of gripping force, the effects of the spring are negligible.

Answer 1

hat gum a 15 2.07 35 39 F= 46 1 bs and Point At Uppen handle: henigun bed fore Vedtial Jorse -37-681 1b (s26 o Fe Camme -33 681 16- 33 681 Ft las 35 Ft 4-1.69 6 Vathul fone Sya 31 K 41.696

17.8138 6 jauo Hantun't Sas (as32x 46 30h 23650 Fr FA At paint ci Horigutn y=Ge A 23.91-J6s

RensTind Jener Hogta atal) FR 4S.36 Jb At pait D: Hengetes 16:51 26.384 bs Vatat 3. 681 Jb **-LC .80 Pesuttut foau =d eb 38 (39-612 5-639 Bolt:(Uppn hundle) Hongatad Vatul Cas d t6 r Sin d x 46 =0-99 lbr Reustount CHonV 4-1.SS Bott Hontul =Cossx46-34.9 Vaty

(Herlt jt(Vatal) Reuleut 4s'-99 on thu' oody Veata! hortguntud thui At thui body pont jaw -32 681lb 188 Uppn 1-8 Lun hudle 38-97 25*-346 PEJG 26-38ty37 6allunle (loik) Linelbndhe 4136 45 Iune26-30 D A bolt bol t Upen bot 41.S6 0.99 Bolt bolt 34, 91 29.9 49 AL