Here ,
initial distance , di = 0.170 m
final distance , df = sqrt(0.28^2 + 0.29^2)
df = 0.403 m
Initial potential energy , Ui =k*q1*q2/di
Ui = 9*10^9 * 4 *10^-6 * (-4.60 *10^-6)/0.170
Ui = -0.974 J
final potential energy , Uf = k*q1*q2/df
Uf = 9*10^9 * 4 *10^-6 * (-4.60 *10^-6)/0.403
Uf = -0.411 J
work done by the electric field = -change in potential energy
work done by the electric field = 0.974 - 0.411
work done by the electric field = 0.563 J
the work done by the electric field is 0.563 J
Exercise 23.1 Part A A point charge with a charge q1 = 4.00 mu C is...
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