Homework Answers
38) Since |ts| < |tc|
If |ts| > |tc| we reject the hypothesis but |ts| < |tc| we don't have evidence to reject the hypothesis.
39)
It is given the sample data and we have given sample standard deviation so t test is used
40)
C = 1 - 0.01 = 0.99
> qt(.99,23)
[1] 2.499867
> 2.4999*40/sqrt(23)
[1] 20.85061
> 20.85/504
[1] 0.04136905
1 - 0.04136905 = 0.9586
Hence it is above 95%
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38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? a)...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason?...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample s.d. b) t-test because the sample is small e) none...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason?...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample s.d. b) t-test because the sample is small e) none...
Please give the answer according to the choices given 38-40 Co 38. Does Christine now reject...
Please give the answer according to the choices given
38-40
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample...
So is the study inconclusive? The class decides that the sample size was too small and...
So is the study inconclusive? The class decides that the sample size was too small and believe many more joeys should be sampled Well Christine can't do this all by herself (finding all these joeys and weighing them is exhausting workl) so she and 22 of her classmates all go to Australia and each of them finds and weighs 23 joeys (think about that - what is the sample size going to be?), They compile all their data, and determine...
Please ignore the circled answers. I am checking my results. d reject because ts eject So...
Please ignore the circled answers. I am checking my
results.
d reject because ts eject So is the study inconclusive? The class decides that the sample size was too small and believe many more joeys s and weighing them is o Australia and each of them finds and weighs 23 ile all their data and determine the ioeys think about that -what is the sample size going to be?). They compi combined average weight to he 504.09 mg with the...
please answer 38, thanks. 26. Given a test statistic of 2.09 paired with a crtical z-score...
please answer 38, thanks.
26. Given a test statistic of 2.09 paired with a crtical z-score of 2 33 on a one tailed test, then the conclusion fail to reject H. at α-1% b)fail to reject H,at α-5%e reject KedacceptH,ata-1% d) reject, and accept H. at a " 5% At a 95% a) e) nooc of these 27. interval, how often would we expect u to 5% 95% c)1% fall outside the inerval estimate? 28. We are allowed to use...
of 2.33 on a one tailed test, then the conclusion 26. Given a test statistic of...
of 2.33 on a one tailed test, then the conclusion 26. Given a test statistic of 2.09 paired with a critical z-score a) fail to reject Ho at α-1% At a 95% confidence interval, how often would we expect μ to fall outside the interval a) 95% 27. We are allowed to use the normal distribution if a) σ is known 28. When we determine a p-value for an h a) a 29. What action will cause the confidence interval...
a. 26 Given a test statistic of 2.09 paired with a critical z-score of 233 on...
a. 26 Given a test statistic of 2.09 paired with a critical z-score of 233 on a one tailed test, then the c fail to reject at α-1% b)fail to reject Hua-5% reject and accept H. at a-5% e) noot ofthese ,reject ILndecepti,re.rs 27. At a 95% a) 1A interval, how often would we expect 95% c)1% to 28. We are allowed to use the normal distribution if d)90% e)10% ơīs known b) n-500 c α b) df c) the-test...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample s.d. b) t-test because the sample is small e) none...
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample s.d. b) t-test because the sample is small e) none...
Please give the answer according to the choices given
38-40
Co 38. Does Christine now reject or fail to reject (FTR) Ho and for what reason? FTR because isl<\td b) reject because p-value< α reject because s) reject because p-value >a c) FTR because p-value<a weighs 23 data, and determine the 39. What test do they use and why? a) t-test because it's a sample s.d. c) z-test because it's a large enough sample d) z-test because it's a sample...
So is the study inconclusive? The class decides that the sample size was too small and believe many more joeys should be sampled Well Christine can't do this all by herself (finding all these joeys and weighing them is exhausting workl) so she and 22 of her classmates all go to Australia and each of them finds and weighs 23 joeys (think about that - what is the sample size going to be?), They compile all their data, and determine...
Please ignore the circled answers. I am checking my
results.
d reject because ts eject So is the study inconclusive? The class decides that the sample size was too small and believe many more joeys s and weighing them is o Australia and each of them finds and weighs 23 ile all their data and determine the ioeys think about that -what is the sample size going to be?). They compi combined average weight to he 504.09 mg with the...
please answer 38, thanks.
26. Given a test statistic of 2.09 paired with a crtical z-score of 2 33 on a one tailed test, then the conclusion fail to reject H. at α-1% b)fail to reject H,at α-5%e reject KedacceptH,ata-1% d) reject, and accept H. at a " 5% At a 95% a) e) nooc of these 27. interval, how often would we expect u to 5% 95% c)1% fall outside the inerval estimate? 28. We are allowed to use...
of 2.33 on a one tailed test, then the conclusion 26. Given a test statistic of 2.09 paired with a critical z-score a) fail to reject Ho at α-1% At a 95% confidence interval, how often would we expect μ to fall outside the interval a) 95% 27. We are allowed to use the normal distribution if a) σ is known 28. When we determine a p-value for an h a) a 29. What action will cause the confidence interval...
a. 26 Given a test statistic of 2.09 paired with a critical z-score of 233 on a one tailed test, then the c fail to reject at α-1% b)fail to reject Hua-5% reject and accept H. at a-5% e) noot ofthese ,reject ILndecepti,re.rs 27. At a 95% a) 1A interval, how often would we expect 95% c)1% to 28. We are allowed to use the normal distribution if d)90% e)10% ơīs known b) n-500 c α b) df c) the-test...
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