Question

can anyone help me solve this?

This Exam is open book, open notes, and open IB WC LAND Capacitors Resistors V-IR Q-CV C. - C C/C+C2) R. - Ri+R2 Series Cp - C1+C2 Parallel Ro-RR (R+R) 1. Use the circuit to fill in the missing information in the table below. А ЗuFв бF HE НЕ D luF C12uF A НЕ E 3F F 60С HE Η 1μF G 18uC I 6V LE 24V Capacitor Charge Voltage Capacitance ЗuF 6uF 12uF luf 3uF F 60°C 18uC G luf 6V Battery 24V

Answer 1

A But bur SATA Слко наt on same potential due to parallel R dan laur Connection Charge ont HECU ay love Sesilec (5) (6) Ton 64C capacitance of I LE Cara - azuf ou C and Cf are in Polentia across G, .24-6= 100 oo shorgon for th=/ GRE (+5 Chargeon G.lazione, Az = Cif XV So capacitante, c= 10 = 1 MF I bo= 50 x 24 not paint o aditha | 2.5 = - 18 = 0,+Qh=0,+6 d.5C+12.5=50 1Q1 = 124c = QZ c=5uFI This is the capacitance The charge on F, Of=Q₂=6046 Also Qza Autos potential across paint and A and B in series, RAB= (36) 24-60=20-12 Vi= 12 valt Slike i Qu = CABX VIR I Qu=2x12 -zucht IF \tев - 2 ме D&E in parallel Ede = 1+3=44F Cor and le are in series, EDF = Ca nh) = (212) Corazu CDE and eas are in parallel Crated a 3+2=5 ur and sosiet Ives in a fusamet

Ad paint & Outas y oca Qq - Qu=60-24=364 Coccole on Voltage of C, Vc = Doç - 36 = 3 rout on Capacuor sand & are on some palentas difference since her Q6= 07. Also Qs = Qotor ( By junctionsule) 365 064896 5) Q6 = 34 - 12MC, Q7 = 396=3x12=3646 vall difference across D882 v= Q = 36 = 12volt Coprindur voltage (out (AC) | Charge luo १५ 24 Copoautonen 3 MF 36 12 36 60 oslal al c/o/e6 { les-ml-12 I Battery