x component = u cos(theta ) = 332 cos(37) = 265.15 m/s
y component = u sin(theta) -g t = 332 sin(37) - (9.81 x 28.4) = -78.52 m/s
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SOLUTION :
Shell is fired at an angle of 37º and speed of 332 m/s.
upward. It travels for 28.4 seconds and explodes.
So,
horizontal speed of shell , Vh = 332 cos (37) = 265.1470 m/s
vertical speed of shell , Vv = 332 sin (37) = 199.8026 m/s
Coordinates of explosion point relative to firing point(0, 0) :
X - component of shell at explosion point
= Horizontal distance moved by shell
= Horizontal speed * time
= 265.1470 * 28.4
= 7530.17 meters (ANSWER)
Y-component of shell at explosion point
= vertical distance travelled by shell
= u t - 1/2 g t^2 ; (u = Vv)
= (199.8026)(28.4) - 1/2 * 9.8 * (28.4)^2
= 1722.25 meters. (ANSWER).
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