An artillery shell is fired with an initial velocity of 300 m/s at 48.0° above the horizontal. To clear an avalanche, it explodes on a mountainside 37.0 s after firing. What are the x- and y-coordinates of the shell where it explodes, relative to its firing point?
x=?
y=?
SOLUTION :
Shell is fired at an angle of 48º and speed of 300 m/s.
upward. It travels for 37 seconds and explode.
So,
horizontal speed of shell , Vh = 300 cos (48) = 200.7392 m/s
vertical speed of shell , Vv = 300 sin (48) = 222.94345 m/s
Coordinates of explosion point relative to firing point(0, 0) :
X = Horizontal distance moved by shell = Horizontal speed * time
= 200.7392 * 37 = 7427.35 meters
Y = vertical distance travelled by shell
= u t - 1/2 g t^2 ; (u = Vv)
= (222.94345)(37) - 1/2 * 9.8 * (37)^2 = 1540.81 meters.
Hence, X, Y coordinates of explosion point are : 7427.35 m and 1540.81 m respectively.
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