Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and the standard deviation is $2.00.
Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount...
Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and the standard deviation is $2.00. What is the probability that a randomly selected person spent between $9.00 - $11.50? 0.037 0.117 0.214 0.135
Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and the standard deviation is $2.00. What is the amount that a randomly selected customer must pay for a meal to be in the top 10% of expenditures for a restaurant meal? $17.77 $12.94 $15.12 $16.36
Consumers spend an average of $13.80 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and the standard deviation is $2.00. Between what two values will the middle 95% of the amounts spent fall? $9.88 to $17.72 $8.22 to $16.59 $9.51 to $18.69 $7.75 to $17.45
6.9 Consumers spent an average of $14.99 on a meal at a restaurant in 2013. (Data extracted from bit.ly/1hObH22.) Assume that the amount spent on a restaurant meal is normally distributed and that the standard deviation is $2. a. What is the probability that a randomly selected person spent more than $15? b. What is the probability that a randomly selected person spent between $10 and $12? c. Between what two values will the middle Ninety-five percent of the amounts...
One year consumers spent an average of $21 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and that the standard deviation is $4. Complete parts (a) through (c) below. a. What is the probability that a randomly selected person spent more than $ 22? P(X> $22 )=___________________ (Round to four decimal places as needed.) b. What is the probability that a randomly selected person spent between $11 and $ 19?P($11<X<...
One year consumers spent an average of $23 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $5. Complete parts (a) a. What is the probability that a randomly selected person spent more than $25?
One year consumers spent an average of $22 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $5. Complete parts (a) through (c) below. a. What is the probability that a randomly selected person spent more than $23? P(Xgreater than$23)equals 0.4207 (Round to four decimal places as needed.) b. What is the probability that a randomly selected person spent between $8 and $21? P($8less thanXless...
A study found that consumers spend an average of $23 per week in cash without being aware of where it goes. Assume that the amount of cash spent without being aware of where it goes is normally distributed and that the standard deviation is $6 a. What is the probability that a randomly selected person will spend more than $27?
A study found that consumers spend an average of $22 per week in cash without being aware of where it goes. Assume that the amount of cash spent without beir aware of where it goes is normally distributed and that the standard deviation is $6. Complete parts (a) through (c). a What is the probability that a randomly selected person will spend more than $23 PX>$23)(Round to four decimal places as needed b. What is the probability that a randomly...
A study found that consumers spend an average of 2 per week in cash without being aware of where it goes. Assume that the amount of cash spent without being aware of where it goes is normally debuted and that the standard deviation is st Come parts though) POX > 525)= Cound to four decimal places as needed) What is the probably that a randomly selected person will spend between 513 and 5199 P1313X319) Round tour de s as needed)...