Question

18. What is the molarity of all the species present in 0.20 M H2TeOz (Ka, = 2 x 10-3 and Kaz = 1 x 10-8)? 19. For a 0.25 M H2
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H HTes H2Te3 t20 O 20 Oc 20-X e 2/03 (0.20-x) y2x10-4x100 CH*J-C J 0-903 M for 2ndloisociabon HtTeo2 HTeo Oa 01903 0-0/903 9=

O. -Ay o-x Ka, HHso 2 ) 3i2 - 35x130 THJ = CHSo J 0-osorr O -.oso8? 6.19912M H2S0320 19912M 2 disoahon Sog 2 0o588-x 63X168 C

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