Homework Answers
The electric potential due to a point charge at a distance r is
given by,
V = kq/r
The net potential at the origin due to the charges is,
V = kq1/r1 + kq2/r2 + kq3/r3
= 9*10^9 (5.02*10^-12/2.4 + 4.4*5.02*10^-12/4.8 -
2.8*5.02*10^-12/2.4)
= 9*10^9*5.02*10^-12/2.4 (1+2.2-2.8)
= 0.00753 Volts or 7.53 mV
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Question 12 In the figure what is the net electric potential at the origin due to...
Your answer is partially correct. Try again. In the figure what is the net electric potential...
Your answer is partially correct. Try again. In the figure what is the net electric potential at the origin due to the circular arc of charge Q1- +3.53 pC and the two particles of charges Q2 3.1001 and Q3 -2.90Q1? The arc's center of curvature is at the origin and its radius is R 7.70 m; the angle indicated is 619.0 Qi 2.00R Number 9563 1Units
In the figure, what is the net electric potential at the origin due to the circular...
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Problem 27 Chapter 24, Problem 027 In the figure three thin plastic rods form quarter-circles with...
Problem 27
Chapter 24, Problem 027 In the figure three thin plastic rods form quarter-circles with a common center of curvature at the origin. The uniform charges on the rods are Q1 +52 nC,Q2 +2.8Q1, and Q3 =-87Q1. What is the net electric potential at the origin due to the rods? (cm) 4.0 2 20 1.0 Units Number the tolerance is +/-2%
Question 9 In the figure what is the net electric potentia! at point p due to...
Question 9 In the figure what is the net electric potentia! at point p due to the four particles if V-0 at infinity, q 7.24 fC, and d 4.20 cm? -q -9 +9 Number Units the tolerance is +/-596
Three point charges, q1 = -4.19nC, q2 = 5.31nC and q3 = 2.70nC are aligned along the x axis as shown in the figure below. Assume that L1 = 0.545m and L2 = 0.755m.
Three point charges, q1 = -4.19nC, q2 = 5.31nC and q3 = 2.70nC are aligned along the x axis as shown in the figure below. Assume that L1 = 0.545m and L2 = 0.755m. Calculate the electric field at the position (2.13m, 0). Calculate the magnitude of the electric field at the position (0, 2.13m). Calculate the angle of the electric field with respect to the positive x-axis at this position (0, 2.13). A line of positive charge is formed into a semicircle of...
Solve problem 2 and 3 with details . Thank you Notre Dame University-Louaize Faculty of Natural& Applied Sciences Department of Physics& Astronomy PHS 212-Electridity & Magnetism Fall 201...
Solve problem 2 and 3 with details . Thank you
Notre Dame University-Louaize Faculty of Natural& Applied Sciences Department of Physics& Astronomy PHS 212-Electridity & Magnetism Fall 2018 Final Exam (22Dec18, 120min) Closed-book, Closed-notes, Close-everything Exam List in detail any assumptions that you make. Show all your work. You can use a calcalater Useful Constants: e1.6x 10C, charge of 1 electron k-8.9875x10 Nm/C2 mass of 1 electron: 9.11 x 10 kg 1. Three point charges, q +15 C, q +35...
1. Figure G: The ideal battery has an emf of 14 V. What is the current...
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Your answer is partially correct. Try again. In the figure what is the net electric potential at the origin due to the circular arc of charge Q1- +3.53 pC and the two particles of charges Q2 3.1001 and Q3 -2.90Q1? The arc's center of curvature is at the origin and its radius is R 7.70 m; the angle indicated is 619.0 Qi 2.00R Number 9563 1Units
In the figure, what is the net electric potential at the origin due to the circular arc of charge Q_1 = -2.50 pC (arc length is 90 degree, going from 110 degree to 200 degree) and the two particles of charges Q_2 = +4.00 Q_1 and Q = -2.00 Q ? The arc's center of curvature is at the origin and its radius is R = 2.00 m; the angle indicated is theta = 20.0 degree. [Explain your choice of...
Problem 27
Chapter 24, Problem 027 In the figure three thin plastic rods form quarter-circles with a common center of curvature at the origin. The uniform charges on the rods are Q1 +52 nC,Q2 +2.8Q1, and Q3 =-87Q1. What is the net electric potential at the origin due to the rods? (cm) 4.0 2 20 1.0 Units Number the tolerance is +/-2%
Question 9 In the figure what is the net electric potentia! at point p due to the four particles if V-0 at infinity, q 7.24 fC, and d 4.20 cm? -q -9 +9 Number Units the tolerance is +/-596
Solve problem 2 and 3 with details . Thank you
Notre Dame University-Louaize Faculty of Natural& Applied Sciences Department of Physics& Astronomy PHS 212-Electridity & Magnetism Fall 2018 Final Exam (22Dec18, 120min) Closed-book, Closed-notes, Close-everything Exam List in detail any assumptions that you make. Show all your work. You can use a calcalater Useful Constants: e1.6x 10C, charge of 1 electron k-8.9875x10 Nm/C2 mass of 1 electron: 9.11 x 10 kg 1. Three point charges, q +15 C, q +35...
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