Question

P.1 (20 points) In the figure, what is the net clectric potential at the origin due to the circular arc of charge Q 2.50 pc (arc length is 90 going from 110 to 200) and the two particles of charges +4.000 and Q, -2,000 The arcs center of curvature is at the origin and its radius is R 2.00 m the angle indicated is 20.0 [Explain your choice of equations1 00R
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Answer #1

Net electric Potential is given as

Vnet = V1 + V2 + V3

Vnet = kQ1/R + kQ2/(2R) + kQ3/R

Vnet = kQ1/R + kQ2/(2R) + k Q3/R

Vnet = (9 x 109) (1/2) ((- 2.50 x 10-12) + 4(- 2.50 x 10-12)/2 + (-2) (- 2.50 x 10-12))

Vnet = - 0.01125 Volts

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