Question

USE EXACT ANALYSIS Use 4 decimal places, no commas. Given: Single-stage, voltage-divider biased, common collector amplifier with a. VCC = 15V b. R1 55 kohms c. R2 15 kohms d. RE 1.5 kohms e. Rs = 14 ohms f. RL = 500 ohms g. DC Beta = 50 h, AC Beta = 100 *C1 and C2 are coupling capacitors. C3 is bypass capacitor Required: A. VTH =[a] V B. RTH =[b] kohms C. IE [c] mA D. VC =[d] V E. VCE =[e] V F. re' [f ohms G. Rin(base) [g] kohms H. Rin(tot) [h] kohms I. Voltage gain (Av) = [i] J. Attenuation (Att) = [H] K. Overall voltage gain (AVT) = [k] L. IL/le = [] M. le/lb = [m] N. lb/Is [n] O. Overall current gain (AIT) = [0] P Overall power gain (APT) = [p]

Answer 1

divider hiased Garnma e single stage rtge ernitter ld eov VCCs1SV Rs 3 biaging DC- open the c beComes --v<< z 15V R-2.52 55K 1512 15 X A 15 tn 15X IStn+5ste 14 55K 15 3.214V 11.78 t

Vec 15V H782 1Ste 3.2hv VB 3.214-0.1 1-78 K -5 tn Re RE +50 I.453MA Itp 50 R1453 51 IC=424 0,028 mA Ve =Vec-R 15-(1424ma)(2.5t2) TERE Ve ( )ssh Ve 2.171V

VE-Ve - 11.44- 2- 7v 9.261V VBEVVE Vt VeVBEtVE Ve2-8 71 2 Smv 1.424MA Ic 7YT at Yoom 25mv gm 0.05696Y P 1m 50 O.0 5696 re877.8 CC21 3 au shat naly AL RL h-pamt Mady

USI PTg 2.SK RS 28K VB 8172 2.5K 2SK500n 3 K 18.667 3.33XP 8 83-33 TB X500 L 6668 e (817) Vn e VL -41666 Vio 811 s Ava-47.51 11 1-78 K ONendl tv Avs 2 Ay A 1118 Kt15 Avs

RS RB (n8KA 1811-82) Rin VSI 831.99 n R. otal Ri 83-33Tp (6.6671 4.1117 16.667 h 216.467 2-