A cup containing 200 g of water is sitting on your dining room table. After carefully measuring its temperature to be 20-degrees Celsius, you leave the room. Returning 10 minutes later, you measure its temperature again and find that it is now 25-degrees Celsius. What can you conclude about the amount of heat added to the water? (HINT: trick question)
Solution-
heat added = Q = m.Cp.dT
Cp of water = 4.18 J/g.c
so heat added = 200 x 4.18 x (25 - 20)
= 4180 J = 4.18 KJ
Therefore we can conclude that the water was at a lower temperature than the temperature of the atmosphere.
Hence water took 4.18 KJ of heat from the air and got heated to 5-degree celcius
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