Problem 7-11 (Algorithmic)
Hart Manufacturing makes three products. Each product requires manufacturing operations in three departments: A, B, and C. The labor-hour requirements, by department, are as follows:
Department | Product 1 | Product 2 | Product 3 |
A | 1.60 | 3.10 | 2.10 |
B | 2.20 | 1.20 | 2.70 |
C | 0.35 | 0.35 | 0.35 |
During the next production period, the labor-hours available are 470 in department A, 370 in department B, and 70 in department C. The profit contributions per unit are $27 for product 1, $30 for product 2, and $32 for product 3.
Max | P1 | + | P2 | + | P3 | ||
s.t. | |||||||
P1 | + | P2 | + | 2.1P3 | ≤ | ||
2.2P1 | + | P2 | + | P3 | ≤ | ||
P1 | + | 0.35P2 | + | P3 | ≤ | ||
P1, P2, P3 ≥ 0 |
Max | P1 | + | P2 | + | P3 | + | y1 | + | y2 | + | y3 | ||
s.t. | |||||||||||||
P1 | + | P2 | + | 2.1P3 | ≤ | ||||||||
2.2P1 | + | P2 | + | P3 | ≤ | ||||||||
P1 | + | 0.35P2 | + | P3 | ≤ | ||||||||
P1 | + | y1 | ≤ | ||||||||||
P2 | + | y2 | ≤ | ||||||||||
P3 | + | y3 | ≤ | ||||||||||
P1, P2, P3 ≥ 0; y1, y2, y3 = 0, 1 |
a) Linear Programming model is following:
Max 27P1+30P2+32P3
s.t.
1.6P1+3.1P2+2.1P3 <= 470
2.2P1+1.2P2+2.7P3 <= 370
.35P1+.35P2+.35P3 <= 70
P1, P2, P3 >= 0
b) Solution of the linear program using Excel Solver is following:
FORMULAS:
E3 =SUMPRODUCT(B3:D3,$B$9:$D$9) copy to E5:E7
P1 = 76
P2 = 88
P3 = 36
Profit = $ 5,844
c) Total profit contribution after taking into account the setup costs = 5844 - (420+570+620) = $ 4,234
d)
Mixed-integer programming model is following:
Max 27P1+30P2+32P3-420y1-570y2-620y3
s.t.
1.6P1+3.1P2+2.1P3 <= 470
2.2P1+1.2P2+2.7P3 <= 370
.35P1+.35P2+.35P3 <= 70
P1-185y1 <= 0
P2-160y2 <= 0
P3-150y3 <= 0
P1, P2, P3 >= 0
y1, y2, y3 = 0,1
e) Solution using Excel Solver is following:
FORMULAS:
H3 =SUMPRODUCT(B3:G3,$B$12:$G$12) copy to H5:H10
P1 = 100
P2 = 100
P3 = 0
Profit = $ 4,710
The profit is increased by = 4710-4234 = $ 476
Problem 7-11 (Algorithmic) Hart Manufacturing makes three products. Each product requires manufacturing operations in three departments:...
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