The length of a simple pendulum undergoing SHM is 2.0 m. If the amplitude is 15...
The length of a simple pendulum undergoing SHM is 2.0 m. If the amplitude is 15 degrees, what is the gravitational potential energy of the pendulum's bob if it has a mass of 0.100 kg? How fast does the pendulum's bob pass through the equilibrium position?
Homework Answers
formula for potential energy of simple pendulum is
PE = mgh
= mg L ( 1- cos theta)
= 0.1(9.8)(2.0)( 1- cos15)
=0.0667 J
(b)
v= sqrt 2gh
= sqrt 2g L ( 1- cos theta)
= sqrt 2 (9.8) 2.0( 1- cos 15)
=1.15 m/s
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