The velocity of the bob of a simple pendulum of length 0.25 m at its lowest position is 0.2 m/s. What is the angular amplitude of the oscillation? This problem can be solved by using either (1) energy conservation or (2) the equations of SHM. Solve it both ways and compare the answers. Explain the difference if any.
The velocity of the bob of a simple pendulum of length 0.25 m at its lowest...
The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of 305 grams, and it is released at an angle of 11° to the vertical. (a) With what frequency does it vibrate? Assume SHM. Hz (b) What is the pendulum bob's speed when it passes through the lowest point of the swing? m/s (c) What is the total energy stored in this oscillation, assuming no losses? J My Notes Ask Your Teacher 8. -13 points...
The length of a simple pendulum undergoing SHM is 2.0 m. If the amplitude is 15 degrees, what is the gravitational potential energy of the pendulum's bob if it has a mass of 0.100 kg? How fast does the pendulum's bob pass through the equilibrium position?
Chapter 10, Problem 45 GO The length of a simple pendulum is 0.75 m and the mass of the particle (the "bob") at the end of the cable is 0.28 kg. The pendulum is pulled away from its equilibrium position by an angle of 9.1° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) what is the angular frequency of the motion? (b) Using the position of the...
The length of a simple pendulum is 0.75 m and the mass of the particle (the "bob") at the end of the cable is 0.33 kg. The pendulum is pulled away from its equilibrium position by an angle of 9.1° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point...
he length of a simple pendulum is 0.65 m and the mass of the particle (the “bob”) at the end of the cable is 0.20 kg. The pendulum is pulled away from its equilibrium position by an angle of 7.7° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point...
Chapter 10, Problem 45 GO The length of a simple pendulum is o.70 m and the mass of pendulum is pulled away from its equilibrium position by an angle of 8.8° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy...
Please solve carefully 6, A damped simple pendulum consists of a bob (m-2.55kg), a length (L = 4m), and a damping force (F- bv). Initially, it oscillates with an amplitude of 16.0 cm; because of the damping, the amplitude falls to three-fourths of this initial value at the completion of four oscillations. (a) What is the value of b? (b) How much energy has been "lost" during these four oscillations? 6, A damped simple pendulum consists of a bob (m-2.55kg),...
A certain simple pendulum consists of a small 750.0 ? bob that swings on the end of a 25.0 ?? string. The small amplitude of the oscillations of this pendulum decays to half its original value after 45.0 oscillations. The angular position of the pendulum as a function of time, ?(?), can be expressed as follows. ?(?) = ??0 ? − ??/2m cos(? ′ ? + ?) ??0 is the original angular amplitude. ? is the time, and ? is...
A simple pendulum with mass m = 1.8 kg and length L = 2.77 m hangs from the ceiling. It is pulled back to an small angle of θ = 9° from the vertical and released at t = 0. 1) What is the period of oscillation? Answer= 3.34 s 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? Answer= 2.76 N 3) What is the maximum speed of the pendulum?...
A simple pendulum has a length L and a mass m. At its highest point, the pendulum mass is 0.25L above its lowest point (see figure below). What is the speed of the mass when it is at its lowest point? Express your answer in terms of m, L, and g. v = The position of a mass-on-a-spring oscillator is given by y = A sin(20t), where the value of t is in seconds and A = 0.44 m. What...