Question

72 q1

In the figure, particle 1 of charge q1 = 2.00×10-5 C and particle 2 of charge q2 = 4.00×10-5 C are fixed to an x axis, separated by a distance d = 0.100 m.
Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left.

What is E(-0.020)?

What is E(0.050)?

What is E(0.130)?

0 0
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Answer #1

242 0.020)2 0.020十0-10の2 E=_ 475X10 Nic | at k=-002 EE 92 X2d)2 aXIo 0-190-0.l0o 0-1302 2 2

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