Question

92 g1 In the figure, particle 1 of charge q1 -8.10x10-5 c and particle 2 of charge q2- 3.24x10-4 c are fixed to an x axis, separated by a distance d 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.100)1? 590490 N/C Submit Answer Incorrect. Tries 1/5 Previous Tries What is E(-0.050)? Submit Answer Tries 0/5 What is E(0.070)? Submit Answer Tries 0/5 What is E(0.130)
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
92 g1 In the figure, particle 1 of charge q1 -8.10x10-5 c and particle 2 of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In the figure, particle 1 of charge q1 = 2.00×10-5 C and particle 2 of charge...

    In the figure, particle 1 of charge q1 = 2.00×10-5 C and particle 2 of charge q2 = 4.00×10-5 C are fixed to an x axis, separated by a distance d = 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.020)? What is...

  • 72 7l In the figure, particle 1 of charge q1-4.80 x 10-5 C and particle 2...

    72 7l In the figure, particle 1 of charge q1-4.80 x 10-5 C and particle 2 of Charge q2-9.60x10-5 C are fixed to an x axis, separated by a distance d-0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is F-0.100)? Submit Answer Incorrect. Tries...

  • 72 7l In the figure, particle 1 of charge q1 3.90x10-5 C and particle 2 of...

    72 7l In the figure, particle 1 of charge q1 3.90x10-5 C and particle 2 of charge q2-1.56x10-4 C are fixed to an x axis, separated by a distance d-o.100 m Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.100)? 1.35E8 N/C Submit Answer Incorrect....

  • In the figure, particle 1 of charge q1 = 1.10×10-5 C and particle 2 of charge...

    In the figure, particle 1 of charge q1 = 1.10×10-5 C and particle 2 of charge q2 = 3.30×10-5 C are fixed to an x axis, separated by a distance d = 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.100)? What is...

  • g2 gl In the figure, particle 1 of charge q1-8.20x10-5 C and particle 2 of charge...

    g2 gl In the figure, particle 1 of charge q1-8.20x10-5 C and particle 2 of charge q2 . 3.28x10-C are fixed to an x axis, separated by a distance d 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left What is E(-0.100)? 1.47x10 N/C You are...

  • In the figure, particle 1 of charge q1 = 9.50×10-5 C and particle 2 of charge...

    In the figure, particle 1 of charge q1 = 9.50×10-5 C and particle 2 of charge q2 = 2.85×10-4 C are fixed to an x axis, separated by a distance d = 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.100)? What is...

  • In the figure, particle 1 of charge q1 = 8.00×10-6 C and particle 2 of charge...

    In the figure, particle 1 of charge q1 = 8.00×10-6 C and particle 2 of charge q2 = 4.00×10-5 C are fixed to an x axis, separated by a distance d = 0.100 m. Calculate their net electric field E(x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. What is E(-0.100)?

  • Three particles are fixed on an x axis. Particle 1 of charge q1 is at x...

    Three particles are fixed on an x axis. Particle 1 of charge q1 is at x =-a, and particle 2 of charge q2 is at x = +a If their net electrostatic force on particle 3 of charge+Q is to be zero, what must be the ratio q1/q2, when particle 3 is at x+0.530a? Submit Answer Tries 0/10 If their net electrostatic force on particle 3 of charge +Q is to be zero, what must be the ratio q1/92, when...

  • 01) k 02 » Electric Field of Two Partices 71 In the figure, particle 1 of...

    01) k 02 » Electric Field of Two Partices 71 In the figure, particle 1 of charge q-8.20x10 C and particlke 2 of charge a-3.28x10 C are fixed to an x axis, separated by a distance d-0.100 m their net electric field E(k) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the eft Tries oys...

  • In the following situation, q1 has a charge of 4e and q2 has a charge of...

    In the following situation, q1 has a charge of 4e and q2 has a charge of e. The two point charges are separated by a distance of r=2.7 m. 41 A2 What is the magnitude of the electric field at q2 due to q1? What is the direction of the electric field at q2 due to q1? Submit Answer Tries 0/8 What is the magnitude of the electric field at q1 due to q2? What is the direction of the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT