Consider the reaction of HClO4 with P4O10 to form H3PO4 and Cl2O7. If 5.51 g P4O10 is reacted with excess HClO4 and 6.70 g of H3PO4 is ultimately isolated, what is the percent yield for the reaction?
12HClO4 + P4O10 ------------> 4H3PO4 + 6Cl2O7
according to balanced reaction
283.89 g P4O10 gives 4 x 98 g H3PO4
5.51 g P4O10 gives 5.51 x 4 x 98 / 283.89 = 7.61 g H3PO4
theoretical yield = 7.61 g
actual yield = 6.70 g
% yield = (actual yield / theoretical yield) x 100
% yield = (6.70 / 7.61) x 100
% yield = 89.8 %
Consider the reaction of HClO4 with P4O10 to form H3PO4 and Cl2O7. If 5.51 g P4O10...
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