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Consider the reaction of CS, with Cly to form CCl, and SCI. If 3.30 g CS, is reacted with excess Cl, and 4.51 g of CCI, is ul
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Answer #1

CS₂ +4 Ch c ly + 2SC22 Actual yield of caly = 4.819. Moles of CS2 = 33907 - 33 mer 169m017 1 mole CS2 produces I mole of caly

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