Homework Answers
1st calculate mol of Cl2
Given:
P = 0.532 atm
V = 6.08 L
T = 110.0 oC
= (110.0+273) K
= 383 K
find number of moles using:
P * V = n*R*T
0.532 atm * 6.08 L = n * 0.08206 atm.L/mol.K * 383 K
n = 0.1029 mol
From reaction,
Mol of ClF formed = 2*mol of Cl2 reacted
= 2*0.1029 mol
= 0.2058 mol
Given:
P = 0.847 atm
n = 0.2058 mol
T = 165.0 oC
= (165.0+273) K
= 438 K
use:
P * V = n*R*T
0.847 atm * V = 0.2058 mol* 0.08206 atm.L/mol.K * 438 K
V = 8.7331 L
Answer: 8.73 L
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