1)
Balance reaction is:
2 H2O(l) -> 2 H2(g) + O2(g)
From reaction,
Mol of O2 produced = (1/2)*mol of H2O reacted
= (1/2)*4.12 mol
= 2.06 mol
Given:
P = 1.0 atm
n = 2.06 mol
T = 0.0 oC
= (0.0+273) K
= 273 K
use:
P * V = n*R*T
1 atm * V = 2.06 mol* 0.08206 atm.L/mol.K * 273 K
V = 46.1489 L
Answer: 46.1 L
Only 1 question at a time please
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