Question

What volume of oxygen gas is produced when 24.2 g of mercury(II)oxide reacts completely according to the following reaction at 25 °C and 1 atm? mercury(II)oxide (8) — mercury )+ oxygen() liters oxygen gas

Answer 1

mass of meramy (II)oxide [4go] = 24. 2g. moles of Hgo = mass = 24.28 - malar mass 216.59 g/mol = 0.1117 mole QHgo -> 2Hg +02 2 mole Hgo produces Imole ore I mole ego produces (1) moleo . •1117 mole Hyo produces — -Máx:1117) 5:0558 € molec moles of 2 (n)= 1/6 = 0.5 mole Pressure (p)= I atm. Temperature (T) = 25 °C +25+273 k = 298 K Apply PV=nRT xv=0.0.558 X0:0821 x 298 2 male et on produces v=1.365 Ltr.) Volume of O2,