Fine the concentration of free Ba2+ in 0.07M Na2[Ba(EDTA)] at pH 9.

Question

Question

Fine the concentration of free Ba²⁺ in 0.07M Na₂[Ba(EDTA)] at pH 9.

Answer 1

Answer #1

$log Kf = 7.88 Formation constant of (Ba(EDTA)1-2 = 107.88 = 7.59 <107 At pH =9, the fraction of EDTA that exists Y-4 is = 0.0$

At equivalence point: At equivalence point, all Ba+2 is converted to [Bay-2] complex. So the concentration of Ba+2 is determi

Answer 2

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