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Please answer the following question in detail and show the steps used to do derive the correct answer. Please show all work and circle final answer.
l T-Mobile 21:04 Exit A charge of +8 micro-coulombs is placed at the bottom left corner of a rectangle, a charge of -8 micro-coulombs is placed at the top left corner of a rectangle, a charge of +7 micro-coulombs is placed at the bottom right corner of a rectangle, and a charge of +7 micro-coulombs is placed at the top right corner of a rectangle. The rectangle has a height of 20.6 cm and a width of 12.8 cm. (See sketch). What is the angle of the total electric field at the middle of the left side in degrees measured counter-clockwise from the +x axis? 92 93 height qu 94 width
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Answer #1

As you Know electric field due to the positive charge outwards and due to the the negative charge towards itself(negative charge).

As you know electric field due to the point charge

E=kq/r^2

Here 2. w- 12.gcmso.1280、n 4 OA y- componed of the electnc feldl o1o3 o 1280103)2 EJ = 13 573.39지03 Mic X- Cammed of the ele dyt Heol (v.169) レ 4h E n -y 13573-38χ/o? 364.9 ,35x1, So

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