Question

Find the total capacitance ?tot of the combination of capacitors shown in the figure, where ?1=5.15 μF , ?2=3.55 μF , ?3=9.25 μF , ?4=1.75 μF , ?5=0.750 μF , and ?6=15.0 μF .

Find the total capacitance Ctot of the combination of capacitors shown in the figure, where Ci = 5.15 μF, C2 = 3.55 μF , C3-9.25 μF, C4 1.75 μF , C5-0.750 μF , and C6 15.0 μF C. C. Got = Ci C,

Answer 1

The capacitors C, and C, are parallel to each other and equivalent capacitance is, -0.750 μF+1 5.0μF The equivalent capacitance Csis in series with capacitance Cand the equivalent capacitance is, 456 456 C4+C56 (1.75HF) (15.75 uF) (1.75 μF)-(15.75 μF) 1.575 F The capacitors C and C2 are in series with each other and the equivalent capacitance is, GC2 C12 (5.15uF)(3.55pF) (5.15/F)+(3.55/F) 2.101μF Now the capacitances 5 C and C,are parallel and total capacitance of the circuit is, (2.10LuF)-(9.25 μΡΗ(1.575μF) 12.9 uF