The bromination of anisole is an extremely fast reaction. Complete the resonance structures of the intermediate...
DRAW the four major resonance structures of the sigma complex intermediate in the reaction of anisole with HNO3/H2SO4 to yield p-nitroanisole.
#1. Using curved arrows to symbolize electrons, write a complete reaction mechanism for the bromination of acetanilide to create the product. Include the resonance structures for any charged, delocalized intermediates that are involved. #2. Why does performing the experiment at 0 degrees Celsius help you identify some of the relative rates of reactivity? #3. Explain why a methyl group is a mildly activating group while a methoxy group is strong activating. #4. Explain why-- NH2 act as an activator and--...
Draw both resonance structures of the most stable carbocation intermediate in the reaction shown.
Draw both resonance structures of the most stable carbocation intermediate in the reaction shown.
For the following reaction, which reaction will be faster (Left or Right)? Why? Click on the reaction that will be faster AND the right reason Br +CH OH — ory Br + CH, OH Left Right Because the correct reaction is SN1 and the incorrect reaction is E1. Substitution reactions are more stable than elimination reactions Because the correct reaction doesn't have a double bond. Double bonds make unstable carbocations Because the correct reaction has resonance. The resonance structures allow...
Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3COCI / AICI: CH3 CH30 CH30 • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one. . Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CI CI HNO3 / H2SO4 ON • You do not have to consider stereochemistry....
Also Draw Product A and B Consider the reaction of 2-methyl-1,3-cyclohexadiene with HCl Intermediate A Intermediate B НCІ (Less stable resonance form) (More stable resonance form) CIT CI Product B Product A Assuming that the reaction takes place at a very low temperature, draw the intermediate and product structures, including any formal charges. Draw intermediate A Draw intermediate B Rings Select Draw More Select Draw Rings More Erase Erase Cl C н C н
Draw the least stable resonance form for the intermediate in the following electrophilic substitution reaction. NO2 NO2 Brz/ FeBrz Br . You do not have to consider stereochemistry. Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one. . с ору P aste [] Previous NE Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. OH OH CH3 CH3 CH2 H3PO4 CH3 H3C...
[Review Topics References Draw both resonance structures of the most stable carbocation intermediate in the reaction shown. + HBO • You do not have to consider stereochemistry, . Do not include anionic counter-ions, e.g., I, in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate resonance structures using the symbol from the drop-down menu. . CO /.000- Draw the two major products obtained in the reaction shown....
Question: How is it possible for H2OCl+ to be the active oxidizing agent? Why wouldnt the answer be: NaOCl + CH3COOH ---> HOCL + CH3COONa? How is it possible for HOCL to accept another electron? THE CORRECT ANSWER IS LABLED BELOW: Meta is the least stae intermediate here, but then ortho becomes least stable products. Why is this? Products also are given. Products: он 5.25 % NaOCl Acetone, CH&COOH 9-fluorenone 9-fluorenol c) Provide the balanced chemical equation that accounts for...