*5. Solve the following LP problem using two-phase Simplex method: Maximize f- 4x1x2 X3 subject to...
*5. Solve the following LP problem using two-phase Simplex method: Maximize f= 4x1+ x2 + x3 subject to: 2x1x22x3= 4 Зх1 +3x2 + хз %3D 3, X12 0, х2 20, х3 2 0. [Note: Since a BFS is not available, start Phase I simplex algorithm by introducing variables] two artificial *5. Solve the following LP problem using two-phase Simplex method: Maximize f= 4x1+ x2 + x3 subject to: 2x1x22x3= 4 Зх1 +3x2 + хз %3D 3, X12 0, х2 20,...
5. Solve the following LP problem using Phase I and Phase II simplex algorithm. Maximize f(X) = x1 + x2, subject to: 4x1-2x2 8 XI6 X1, X20 5. Solve the following LP problem using Phase I and Phase II simplex algorithm. Maximize f(X) = x1 + x2, subject to: 4x1-2x2 8 XI6 X1, X20
Problem 3. Solve the following LP by the simplex method. max -x1 + x2 + 2xz s. t x1 + 2x2 – x3 = 20 -2x1 + 4x2 + 2x3 = 60 2xy + 3x2 + x3 = 50 X1, X2, X3 > 0 You can start from any extreme point (or BFS) that you like. Indicate the initial extreme point (or BFS) at which you start in the beginning of your answer. (30 points)
Solve the linear programming problem using the simplex method Maximize P=2x2 + 3x2 + 4x3 subject to X1 + x3 s 12 X2 + x3 s 9 *2, X2, X3 20 Use the simplex method to solve the problem. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. The maximum value of Pis when xy = X2 and x3 = OB. There is no optimal solution
1. Solve the following LP by the simplex method. Min z = 2x2 – Xı – X3 Subject to *1 + 2x2 + x3 = 12 2x1 + x2 – x3 = 6 -X1 + 3x2 = 9 X1, X2, X3 > 0
(10 pts) Using the simplex method, solve the linear programming problem: Maximize z = 30x1 + 5x2 + 4x3, subject to 5x + 3x2 < 40 3x2 + x3 = 25 X1 2 0,X2 2 0,X320
3. Use the two-phase simplex method to solve the following LP. Min z = x1 + 2x2 Subject to 3x1 + 4x2 < 12 2x1 - x2 2 2 X1, X2 20
Solve the following linear programming problem using Two Phase method [12M] Maximize z = 3X1 - 3X2 + X3 Subject to X; + 2x, - xz 25 - 3x; – x2 + x3 54 47, X2, X3 20.
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20