Question

A person walks into a room that has two flat mirrors on opposite walls. The mirrors produce multiple images of the person. Consider only the images formed in the mirror on the left. When the person is 3.80 m from the mirror on the left wall and 6.50 m from the mirror on the right wall, find the distance from the person to the first three images seen in the mirror on the left wall. first image............ m second image........ m third image..............m

Answer 1

but just for the sake of helping out the others who have to slave over physics webassign weekly like me...

first image is found by doubling the distance of the left mirror to the person...
1. 2 x 9 = 18

second one is found by adding 18 to the image of distance produced on the right mirror so..
2. 2 x 8 + 18 = 34

and finally, the third image is found by doubling the distance of the left image produced and adding it to the total distance of the second image, soo...

3. 2 x 9 + 34 = 52

Answer 2

best way to do that is

a) 2(3.8) = 7.6

b) 2(6.5) + (7.6) = 20.6

c) 2(3.8) + (20.6) = 28.2

Answer 3

1st : 4.4 + 4.4 = 8.8
2nd : 21.8
3rd : 30.6