The figure below shows the path
of a beam of light through several layers with different indices of
refraction. (n4 = 1.00)
(a) If θ1 = 31.0°, what is the angle θ2 of the emerging beam?
°
(b) What must the incident angle θ1 be in order to have total
internal reflection at the surface between the medium with n = 1.20
and the medium with n4 = 1.00?
a .
for snell law ,
sin 31 / sin θ2 = n4 / 1 .6 = 1 / 1.6 ; or θ2 = 55.49 degree
b .
since internal reflection occurs ,
θc in n = 1.2 , : sin θc = 1 / 1.2 = 0.8333 ;
in n= 1.4 , sin i / sin θc = 1.2 / 1.4 ; or sin i = 0.8333 * ( 1 .2 / 1.4 ) = 0.714
in n = 1.6 , sin θ1 / sin i = 1.4 / 1.6 or sin θ1 = 0.714 * ( 1.4 / 1.6 ) = 0.625 ;
so incident angle , θ1 = 38.682 ;
The figure below shows the path of a beam of light through several layers with different...
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