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44. A boy floating on a pond watches a fish swim away from him as in Figure P22.44. If the fish is 2.25 m beneath the surface, for what maximum distance d will he be able to see the fish? Neglect the height of the boys eyes above the water. 2.25 m Figure P22.44

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Answer #1

let us assume that the maximum visible distance- d and the depth of the pond-h-2.25m index of refraction of water-1.33 critical angle, θ sin-i |-n => θ=48.753 critical angle is the angle at which light from fish will reflect back int o water from geomentry tan nair-1 ; n =1.33 9 *ater water d htan(0) = 2.25 mx tan( 48.573 )= | 2.566 ml

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fuck                 

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